Gets number of attribute of specified XML node.
Syntax
INT XMLGetAttributeCount(INT hDoc, INT hNode)
hDoc
Handle of the XML document. Returned by XMLCreate or XMLOpen.
hNode
Handle of the node. Returned by XMLGetRoot, XMLGetChild, XMLGetParent or XMLNodeFind.
Return Value
Number of attribute of specified node.
Related Functions
XMLClose, XMLCreate, XMLGetAttribute, XMLGetAttributeName, XMLGetAttributeValue, XMLGetChild, XMLGetChildCount, XMLGetParent, XMLGetRoot, XMLNodeAddChild, XMLNodeFind, XMLNodeGetName, XMLNodeGetValue, XMLNodeRemove, XMLNodeSetValue, XMLOpen, XMLSave, XMLSetAttribute
Example
Following example creates an XML document from local file "H:\Data\books.xml", then selects the first node that matches XPath expression "/bookstore/book/", then gets number of attribute of the node.
INT hDoc, hNode; INT nCount; hDoc=XMLOpen("H:\Data\books.xml"); IF hDoc <> -1 THEN hNode = XMLNodeFind(hDoc,"/bookstore/book/"); IF hDoc <> -1 THEN nCount=XMLGetAttributeCount(hDoc,hNode); End End
See Also
Published June 2018